甲乙两仓共245T大米,甲运出1/4,乙运出1/5后,两仓共剩190T大米,甲乙各有多少T大米?
热心网友
设甲仓有xt大米,所以乙仓有(245-x)t大米,可列245-(1/4)x-(1/5)(245-x)=190解得:x=120t,245-x=125t故甲仓有120t ,乙仓有125t
热心网友
设甲为xT大米,则乙有245-x T大米 (1/4)x+(1/5)(245-x)=245-190 解得:x=120 245-120=125 故甲有120 T,乙有125 T
甲乙两仓共245T大米,甲运出1/4,乙运出1/5后,两仓共剩190T大米,甲乙各有多少T大米?
设甲仓有xt大米,所以乙仓有(245-x)t大米,可列245-(1/4)x-(1/5)(245-x)=190解得:x=120t,245-x=125t故甲仓有120t ,乙仓有125t
设甲为xT大米,则乙有245-x T大米 (1/4)x+(1/5)(245-x)=245-190 解得:x=120 245-120=125 故甲有120 T,乙有125 T