分解因式: 2x^2-5xy+2y^2+5x-y-3

热心网友

解题思路:先分解最高次方项,再分解低次放项。解:2x^2-5xy+2y^2+5x-y-3 =(2x^2-5xy+2y^2)+5x-y-3=(2x-y)(x-2y)+(5x-y)-3=(2x-y)(x-2y)+[(2x-y)×3+(x-2y)×(-1)]-3=(2x-y-1)(x-2y+3)附图上的“ 1”应为“-1”(显示不全)!

热心网友

(2x-y-1)(x-2y+3)

热心网友

2x^2-5xy+2y^2+5x-y-3 原式=(2x-y)(x-2y)+(5x-y)-3  =(2x-y-1)(x-2y+3)