x+1 y+1 x-y--- = --- = --- 2 3 4x和y的值分别是多少.?((用消元法解.谢谢.!
热心网友
设(x+1)/2=(y+1)/3=(x-y)/4=K得K=0代如得X=-1,Y=-1
热心网友
(x+1)/2=(y+1)/3=(x-y)/4由(x+1)/2=(y+1)/3得x=2/3y-1/3将x=2/3y-1/3代入=(y+1)/3=(x-y)/4解得:y=-1将y=-1代入x=2/3y-1/3解得：x=-1此方程组的解为{x=-1 y=-1
热心网友
(x+1)/2=(y+1)/3=(x-y)/4由(x+1)/2=(y+1)/3得，y=x*3/2+1/2由(x+1)/2=(x-y)/4得，y=-2*x-1由上面两式可得：x=-3/7 y=-1/7此即为方程组的解。
热心网友
∵(x+1)/2=(x-y)/4∴x=2-y∵(x+1)/2=(y+1)/3∴(2-y+1)/2=(y+1)/3 y=7/5 x=2-7/5=3/5
热心网友
(x+1)/2=(y+1)/3=(x-y)/43x+3=2y+2-----(1)2x+2=x-yy=-x-2, 代入(1)3x+3=-2x-25x=-5x=-1,y=-1, (代入原方程,检验符合)