热心网友
(x+2y)^2(x-2y)^2-(2x+y)^2(2x-y)^2=[(x+2y)(x-2y)]^2-[(2x+y)(2x-y)]^2=(x^2-4y^2)^2-(4x^2-y^2)^2=[(x^2-4y^2)+(4x^2-y^2)][(x^2-4y^2)-(4x^2-y^2)]=(5x^2-5y^2)(-3x^2-3y^2)=5(x^2-y^2)*(-3)(x^2+y^2)=-15(x^2-y^2)(x^2+y^2)=-15(x^4-y^4)=15(y^4-x^4)
热心网友
(x+2y)^2(x-2y)^2-(2x+y)^2(2x-y)^2=[(x+2y)(x-2y)]^2-[(2x+y)(2x-y)]^2=(x^2-4y^2)^2-(4x^2-y^2)^2=[(x^2-4y^2)+(4x^2-y^2)][(x^2-4y^2)-(4x^2-y^2)]=(5x^2-5y^2)(-3x^2-3y^2)=5(x^2-y^2)*(-3)(x^2+y^2)=-15(x^2-y^2)(x^2+y^2)=-15(x^4-y^4)=15(y^4-x^4)
热心网友
(x+2y)^2*(x-2y)^2-(2x+y)^2*(2x-y)^2=[(x+2y)(x-2y)]^2-[(2x+y)(2x-y)]^2=(x^2-4y^2)^2-(4x^2-y^2)^2=(x^2-4y^2+4x^2-y^2)(x^2-4y^2-4x^2+y^2)=(5x^2-5y^2)(-3x^2-3y^2)=5*(x^2-y^2)(-3)(x^2+y^2)=-15(x^4-y^4)