如图所示,在三角形ABC中,C=90度,CH垂直AB于H,AF平分角BAC交CH于D,ED平行AB交BC于E,求证:CF=BE.
热心网友
如图：CF:FB=AC:AB=AH:AC=DH:DC=BE:CEFB*BE=CE*CF(BE+EF)*BE=(CF+EF)*CFBE^-CF^+EF*(BE-CF)=0(BE-CF)(BE+CF+EF)=0(BE-CF)*BC=0∴BE=CF
热心网友
等我明天空了给你做哈
如图所示,在三角形ABC中,C=90度,CH垂直AB于H,AF平分角BAC交CH于D,ED平行AB交BC于E,求证:CF=BE.
如图：CF:FB=AC:AB=AH:AC=DH:DC=BE:CEFB*BE=CE*CF(BE+EF)*BE=(CF+EF)*CFBE^-CF^+EF*(BE-CF)=0(BE-CF)(BE+CF+EF)=0(BE-CF)*BC=0∴BE=CF
等我明天空了给你做哈