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因为y=[(x+1/2)^2+3/4]/[(x-1/2)^2+3/4],所以y0..........将x^2-x+1乘过来并且化简得:(y-1)x^2-(y+1)x+y-1=0,因为y∈R,所以上述方程的判别式△≥0即y^2+2y+1-4(y^2-2y+1)≥0,所以有:3y^2-10y+3≤0,即：(3y-1)(y-3)≤0,所以1/3≤y≤3..........和取交集得:y∈[1/3,3]
因为y=[(x+1/2)^2+3/4]/[(x-1/2)^2+3/4],所以y0..........将x^2-x+1乘过来并且化简得:(y-1)x^2-(y+1)x+y-1=0,因为y∈R,所以上述方程的判别式△≥0即y^2+2y+1-4(y^2-2y+1)≥0,所以有:3y^2-10y+3≤0,即：(3y-1)(y-3)≤0,所以1/3≤y≤3..........和取交集得:y∈[1/3,3]