1。x^3+x^3y-xy^2-y^32.x^2-y^2+2x+2y最好写出过程，及每步用的方法，如提取公因式
热心网友
1) 改下题:x^3+x^2y-xy^2-y^3=x^2(x+y)-y^2(x+y)=(x^2-y^2)(x+y)=(x-y)(x+y)^22.x^2-y^2+2x+2y=(x-y)(x+y)+2(x+y)=(x+y)(x-y+2)
热心网友
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热心网友
^3+x^2y-xy^2-y^3 =x^2(x+y)-y^2(x+y) (提取公因式x^2,y^2)=(x^2-y^2)(x+y) (提取公因式(x+y) )=(x-y)(x+y)^22.x^2-y^2+2x+2y=(x-y)(x+y)+2(x+y) (因式分解x^2-y^2)=(x+y)(x-y+2) (提取公因式(x+y))
热心网友
1) 改下题:x^3+x^2y-xy^2-y^3 =x^2(x+y)-y^2(x+y) (提取公因式x^2,y^2)=(x^2-y^2)(x+y) (提取公因式(x+y) )=(x-y)(x+y)^22.x^2-y^2+2x+2y=(x-y)(x+y)+2(x+y) (因式分解x^2-y^2)=(x+y)(x-y+2) (提取公因式(x+y))
热心网友
1. 题目是不是打错了，如下会更合适一些：） x^3+x^2y-xy^2-y^3 =(x^3-xy^2)+(x^2y-y^3) =x(x^2-y^2)+y（x^2-y^2） =(x^2-y^2)(x+y) =(x+y)(x-y)(x+y) =(x+y)^2(x-y)2. x^2-y^2+2x+2y =(x+y)(x-y)+2(x+y) =(x+y)(x-y+2)
热心网友
1。x^3+x^2y-xy^2-y^3 ==x^3-y^3+x^2y-xy^2==(x-y)(x^2+xy+y^2)+xy(x-y) ===(x-y)(x^2+2xy+y^2)====(x-y)(x+y)^2 该题的第二项是否错了,否则,不能做因式分解.2.x^2-y^2+2x+2y==(x+y)*(x-y)+2(x+y)====(x+y)(x-y+2)