求最小正数Ｍ

热心网友

y=cosx-√3sinx=2(cosxcosπ/3-sinπ/3sinx)=2cos(x+π/3)(x,y)关于x=π/4的对称点为(π/2-x,y)y=2cos(x+π/3)关于x=π/4的对称方程为y=2cos(π/2-x+π/3)=2cos(x-5π/6)要向右平移π/3+5π/6+2kπk=0时最小正数Ｍ=7π/6