(x+1)(x-3)+(x-1))(x+3)=0
热心网友
(x+1)(x-3)+(x-1))(x+3)=0x^2-2x-3+x^2+2x-3=02x^2=6x^2=3x=根3或x=-根3
热心网友
上面回答都不简洁!(x+1)(x-3)+(x-1))(x+3)=0简化得:2x^2=6x^2=3x=根3或x=-根3 呵呵
热心网友
x^2-2x-3+x^2+2x-3=0,即2x^2-6=0,所以x^2-3=0,即x1=√3,x2=-√3
(x+1)(x-3)+(x-1))(x+3)=0
(x+1)(x-3)+(x-1))(x+3)=0x^2-2x-3+x^2+2x-3=02x^2=6x^2=3x=根3或x=-根3
上面回答都不简洁!(x+1)(x-3)+(x-1))(x+3)=0简化得:2x^2=6x^2=3x=根3或x=-根3 呵呵
x^2-2x-3+x^2+2x-3=0,即2x^2-6=0,所以x^2-3=0,即x1=√3,x2=-√3