已知抛物线x^2=y上有一定点A(-1,1)和两动点P,Q,当PA垂直PQ时,点Q的横坐标的取值范围是?

热心网友

P(p,p^2), Q(q,q^2), [p,q 不等于 -1]PA垂直PQ, == [(p^2-1)/(p+1)]*[(p^2-q^2)/(p-q)] = -1p^2 + (q+1)p + (q+1) = 0(q+1)^2 - 4*(q+1) = 0, (q-3)(q+1) = 0q = 3