已知：(x-4)/(x-2)-(x-8)/(x-6)=(x+1)/(x-1)-(x-5)/(x-7)求：x的值。
热心网友
1-2/(x-2)]-[1-2/(x-6)]=[1+2/(x-1)]-[1+2/(x-7)] 1/(x-6)-1/(x-2)=1/(x-1)-1/(x-7) 4/[(x-6)(x-2)]=-6/[(x-1)(x-7)] 2(x^-8x+7)=-3(x^-8x+12) 5x^-40x+50=0 x^-8x+10=0 x=4±√6
热心网友
(x^2 - 10x + 24 - x^2 + 10x - 16)/(x-2)(x-6) =[(x+1)(x-7)-(x-5)(x-1)]/(x-1)(x-7)8/(x-2)(x-6)=(x^2-6x-7-x^2+6x-5)/(x-1)(x-1)8/(x-2)(x-6)=-12/(x-1)(x-7)8(x-1)(x-7)=-12(x-2)(x-6)2(x-1)(x-7)=-3(x-2)(x-6)2x^2-16x+14=-3x^2+24x-365x^2-40x+50=0x=4±√6
热心网友
此分式方程的每一个分式的分子;分母的第一项都相同,就利用这一点郎简化运算.(x-4)/(x-2)-(x-8)/(x-6)=(x+1)/(x-1)-(x-5)/(x-7)解:方程两边的两个分式分别加上-1;+1,得到-2/(x-2)+2/(x-6)=2/(x-1)-2/(x-7)---1/(x-2)-1/(x-6)=1/(x-7)-1/(x-1)----4/[(x-2)(x-6)]=6/[(x-1)(x-7)]---3(x^2-8x+12)=-2(x^2-8x+7)---5x^2-40x+50=0---x^2-8x+10=0---x=4+'-√6经检验都是原方程的根.
热心网友
初2好象不会1元2次方程
热心网友
已知：(x - 4)/(x - 2) - (x - 8)/(x - 6) = (x + 1)/(x - 1) - (x - 5)/(x - 7)求：x的值。原方程可变形为：[(x - 4)(x - 6) - (x - 2)(x - 8)]/[(x - 2)(x - 6)] = [(x - 7) - (x - 1)(x - 5)]/[(x - 1)(x - 7)](x^2 - 10x + 24 - x^2 + 10x - 16)/(x^2 - 8x + 12) = (x^2 - 6x - 7 - x^2 + 6x - 5)/(x^2 - 8x + 7)8/(x^2 - 8x + 12) = -12/(x^2 - 8x + 7)2x^2 - 16x + 14 = -3x^2 + 24x - 365x^2 - 40x + 50 = 0x^2 - 8x + 10 = 0x1、x2 = 8±2(√6)/2 = 4±√6经检验，x1 = 4 + √6，x2 = 4 - √6都是原方程的根。所以原方程的解为：x1 = 4 + √6，x2 = 4 - √6。
热心网友
(x-4)/(x-2)-(x-8)/(x-6)=(x+1)/(x-1)-(x-5)/(x-7)[1-2/(x-2)]-[1-2/(x-6)]=[1+2/(x-1)]-[1+2/(x-7)]1/(x-6)-1/(x-2)=1/(x-1)-1/(x-7)4/[(x-6)(x-2)]=-6/[(x-1)(x-7)]2(x^-8x+7)=-3(x^-8x+12)5x^-40x+50=0x^-8x+10=0x=4±√6
热心网友
(x^2-10x+24-x^2+10x-16)/(x-8)(x-2)=(x^2-10x-7-x^2+6x-6)/(x-1)(x-7)8(x-1)(x-7)=-13(x-2)(x-6)21x^2-168x+212=0x=4+2√546/21,4-2√546/21